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(x-4)-5(x-4)^1/2=6 solve for x.
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LET (x-1)^1/2 =y
Then solve for y
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not really...
let \[x-4=m\] the equation becomes \[\left( m \right) - 5m^\frac{ 1 }{ 2 } = 6\] on squaring \[m^2 - 5m = 6\]
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therefore \[m=2 , m=2\]
\[m=2 , m=3\] sry now as \[x-4 = m\] we get \[x-4=2 & x-4=3\]
therefore x=6 and x =7
i understand.. thank you!
wheres my medal :D
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gotcha!!
m^2 - 5m = 36 m^2 - 5m - 36 = 0 (m - 9)(m + 4) = 0 m = 9 and m = -4
one thing that was missed was the 6. it wasnt squared.
ya figured it out @franciscanmonk @bevandre sorry
its all good.
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thanks i just needed someone to get me started...but i get it now:)
If the problem expression is:\[(x - 4) - 5*\left(\sqrt{x-4}\right) = 6 \]then x = 40
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