Question

Differentiate, y=e ^3x(2x-1), pls help....

Answer 1

\[e^{3x(2x-1)}\] ?

Answer 2

so \[(e^{f(x)})' = f'(x)e^{f(x)}\]

Answer 3

can you do it now ?

Answer 4

Coolsector......that (2x-1) is not up there with 3x

Answer 5

if you mean e^(3x)*(2x-1) then the result is e^(3x)*(6x-1)
if you meant e^(3x*(2x-1)) then the result is 3*e^(3x*(2x-1))*(4x-1)

Answer 6

ok .. \[(2x-1)e^{3x}\]

Answer 7

let \[f(x) = 2x-1 \]
\[g(x)=e^{3x}\]
\[(f(x)g(x))'=f'(x)g(x)+f(x)g'(x)\]

Answer 8

can you do it now ?

Answer 9

Yes thanks, so here you used product rule?

Answer 10

yes :)

Answer 11

thanks a lot .

Answer 12

yw

Answer 13

for y=e ^3x(2x-1) it is best to do
y=e ^(6x^2-3x) then
y'= [e ^(6x^2-3x)](12x-3) or
y'= (12x-3)e ^(6x^2-3x) ..... ans......or
y'= (12x-3)e ^3x(2x-1 ans...)