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mathslover (mathslover):
@across and @Algebraic!
mathslover (mathslover):
My question is that :
first of all :
\[\large{g_e = \frac{GM_e}{R_e^2}}\]
mathslover (mathslover):
@hartnn
mathslover (mathslover):
@TheViper
mathslover (mathslover):
is it correct hartnn ? I mean for the formula ..
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hartnn (hartnn):
yes, i think....let me confirm
mathslover (mathslover):
*not only hartnn but all
mathslover (mathslover):
confirm it
hartnn (hartnn):
yup, thats correct.
OpenStudy (theviper):
ya it is correct.
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mathslover (mathslover):
derivation of the above formula :
\[\large{F = \frac{GMm}{R^2}}\]
\[\large{\textbf{Since :}\space F = m * g}\]
\[\large{\textbf{hence :} \space \frac{GMm}{R^2}=m*g}\]
\[\large{g = \frac{GMm}{R^2}}\]
mathslover (mathslover):
any mistake here?
OpenStudy (theviper):
g = GM/R^2
now it is correct.
mathslover (mathslover):
oh sorry I meant :
\[\large{g = \frac{GM}{R^2}}\]
mathslover (mathslover):
ok so now ...
\[\large{a=\frac{F}{m}}\]
is it so ?
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OpenStudy (theviper):
ya
hartnn (hartnn):
yes, F=ma
mathslover (mathslover):
Ok now? :
\[\large{a \vector = \frac{F\vector}{m}}\]
mathslover (mathslover):
take that as vector friends:
is it so now?
OpenStudy (anonymous):
OK sooo ?
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OpenStudy (anonymous):
Yes
mathslover (mathslover):
Mikael is
a vector = F vector / m
OpenStudy (anonymous):
Positiff
mathslover (mathslover):
Ok so "no"
since they are vectors
OpenStudy (theviper):
ya it is all right man
wt r u trying to do actually?
going to fail this law ?????????????????????????????????????????????????????????????????
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OpenStudy (anonymous):
??
OpenStudy (anonymous):
hmm - ?
OpenStudy (theviper):
hmmmm-??
mathslover (mathslover):
\[\large{F\vector = a\vector .m}\]
\[\large{\text{Can vectors be divided?}}\]
OpenStudy (anonymous):
Yes by a scalar
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mathslover (mathslover):
wait ... let me type laTex
OpenStudy (anonymous):
la-what ?
mathslover (mathslover):
\[\large{\frac{F\vector}{a\vector}= m}\]
mathslover (mathslover):
is it so now
OpenStudy (anonymous):
NOOO PROHBLEHM VATSOEVER - BECOZE COLLINEAR VECTORS CAN BE DIVIDED BY EACH OZER !!!
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OpenStudy (theviper):
yeah\[\LARGE{\frac{\vec F}{\vec a}=\frac{m \vec a}{\vec a}=m.}\]The way u want;D
mathslover (mathslover):
is it necessary ? that they r collinear vectors?
OpenStudy (anonymous):
MOREOVER, math-loving-krishna-fluting EVEN NON COLLINEAR VECTORS - if we define division as finding a certain transformation matrix with additional constraints
OpenStudy (theviper):
they are collinear man
acceleration is always in the direction of force in inertial frame of reference.
OpenStudy (anonymous):
UZHUALLY though people avoid dividing vectors - because many matices satisfy it, and thus the answer is NOT unique matrix.
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mathslover (mathslover):
EXCELLENT..
OpenStudy (theviper):
since u r writing
f = ma
initially.
OpenStudy (anonymous):
Who's picture is on your pic ?
OpenStudy (anonymous):
And why flute ?
mathslover (mathslover):
Thanks a lot .... i got it now..
GOD "KRISHNA"
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OpenStudy (theviper):
:D
mathslover (mathslover):
He plays flute.... this is his passion
OpenStudy (theviper):
;D
OpenStudy (anonymous):
What is the passion of the butterfly that Dreamed it was Zhuang-tzu ?
OpenStudy (anonymous):
you know that flute notes are actual harmonics of the fundamental tone ?