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Physics 6 Online
mathslover (mathslover):

" Thinking skill " Not now... but a problem

mathslover (mathslover):

@across and @Algebraic!

mathslover (mathslover):

My question is that : first of all : \[\large{g_e = \frac{GM_e}{R_e^2}}\]

mathslover (mathslover):

@hartnn

mathslover (mathslover):

@TheViper

mathslover (mathslover):

is it correct hartnn ? I mean for the formula ..

hartnn (hartnn):

yes, i think....let me confirm

mathslover (mathslover):

*not only hartnn but all

mathslover (mathslover):

confirm it

hartnn (hartnn):

yup, thats correct.

OpenStudy (theviper):

ya it is correct.

mathslover (mathslover):

derivation of the above formula : \[\large{F = \frac{GMm}{R^2}}\] \[\large{\textbf{Since :}\space F = m * g}\] \[\large{\textbf{hence :} \space \frac{GMm}{R^2}=m*g}\] \[\large{g = \frac{GMm}{R^2}}\]

mathslover (mathslover):

any mistake here?

OpenStudy (theviper):

g = GM/R^2 now it is correct.

mathslover (mathslover):

oh sorry I meant : \[\large{g = \frac{GM}{R^2}}\]

mathslover (mathslover):

ok so now ... \[\large{a=\frac{F}{m}}\] is it so ?

OpenStudy (theviper):

ya

hartnn (hartnn):

yes, F=ma

mathslover (mathslover):

Ok now? : \[\large{a \vector = \frac{F\vector}{m}}\]

mathslover (mathslover):

take that as vector friends: is it so now?

OpenStudy (anonymous):

OK sooo ?

OpenStudy (anonymous):

Yes

mathslover (mathslover):

Mikael is a vector = F vector / m

OpenStudy (anonymous):

Positiff

mathslover (mathslover):

Ok so "no" since they are vectors

OpenStudy (theviper):

ya it is all right man wt r u trying to do actually? going to fail this law ?????????????????????????????????????????????????????????????????

OpenStudy (anonymous):

??

OpenStudy (anonymous):

hmm - ?

OpenStudy (theviper):

hmmmm-??

mathslover (mathslover):

\[\large{F\vector = a\vector .m}\] \[\large{\text{Can vectors be divided?}}\]

OpenStudy (anonymous):

Yes by a scalar

mathslover (mathslover):

wait ... let me type laTex

OpenStudy (anonymous):

la-what ?

mathslover (mathslover):

\[\large{\frac{F\vector}{a\vector}= m}\]

mathslover (mathslover):

is it so now

OpenStudy (anonymous):

NOOO PROHBLEHM VATSOEVER - BECOZE COLLINEAR VECTORS CAN BE DIVIDED BY EACH OZER !!!

OpenStudy (theviper):

yeah\[\LARGE{\frac{\vec F}{\vec a}=\frac{m \vec a}{\vec a}=m.}\]The way u want;D

mathslover (mathslover):

is it necessary ? that they r collinear vectors?

OpenStudy (anonymous):

MOREOVER, math-loving-krishna-fluting EVEN NON COLLINEAR VECTORS - if we define division as finding a certain transformation matrix with additional constraints

OpenStudy (theviper):

they are collinear man acceleration is always in the direction of force in inertial frame of reference.

OpenStudy (anonymous):

UZHUALLY though people avoid dividing vectors - because many matices satisfy it, and thus the answer is NOT unique matrix.

mathslover (mathslover):

EXCELLENT..

OpenStudy (theviper):

since u r writing f = ma initially.

OpenStudy (anonymous):

Who's picture is on your pic ?

OpenStudy (anonymous):

And why flute ?

mathslover (mathslover):

Thanks a lot .... i got it now.. GOD "KRISHNA"

OpenStudy (theviper):

:D

mathslover (mathslover):

He plays flute.... this is his passion

OpenStudy (theviper):

;D

OpenStudy (anonymous):

What is the passion of the butterfly that Dreamed it was Zhuang-tzu ?

OpenStudy (anonymous):

you know that flute notes are actual harmonics of the fundamental tone ?

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