Question

√(2x-1)=-3

Help?

Answer 1

by squaring both sides\[2x-1=9\]

Answer 2

\[\sqrt{2x - 1} = -3\]
Square on both sides.
\[2x - 1 = 9\]
Quite simple now, can you do it?

Answer 3

solve for 'x' from here

Answer 4

don't even start this problem
\(\sqrt{2x-1}\) is positive, whereas \(-3\) is negative, so there is no solution

Answer 5

don't square both sides, don't do anything at all
a positive number cannot equal a negative one
say "no solution" and be done

Answer 6

which is good example of making sure you think before you apply some method to a problem

Answer 7

Hmm... the sqrt(9) isn't -3, but I don't see how that disallows -3^2

Answer 8

i am assuming you are looking for a real value for \(x\) and not two complex numbers whose square is \(-3\)

Answer 9

but @satellite73 sir this gives the condition of the question but he needs to solve for 'x'

Answer 10

I didn't think from that point of view.

Answer 11

That was a good point.

Answer 12

Allright, I think I'm getting it. Thanks for all the help. :)

Answer 13

if so (and i really really doubt it) then this method
\[2x-1=9\]
\[2x=10\]
\[x=5\] will certainly not work, and the check is easy
\[\sqrt{2\times 5-1}=\sqrt{9}=3\neq -3\]

Answer 14

hmmmm......

Answer 15

u r right sir :)


sorry!

Answer 16

Excellent answer, satellite73!

Answer 17

@math0101 for steps u can first solve it & prove this wrong or other answer is as @satellite73 sir's answer :)