Could I find the two missing angle measures if I know some of the side lengths of a right triangle?
yes
you would need to know at least 2 side lengths
how would i find this?
by using the appropriate definitions for sine, cosine, and tangent
or, by using the law of sines, in which case, youd still need to know about sines :)
if two of my right triangle's side lengths were 4 and 6. i already know one angle is 90 degrees. so to find the others i would need to use sines?
can you draw a picture and label it using the draw tool?
|dw:1347897696371:dw| hope this helps.
remember, we are trying to find the missing angle measures of this right triangle
had to step away for a minute ...knowing tangent would be useful then
|dw:1347898372808:dw|\[tan = \frac{opposite}{next.to}\]
\[tan(\alpha)=\frac{4}{6}~:~\alpha=tan^{-1}(\frac{4}{6})\] \[tan(\beta)=\frac{6}{4}~:~\beta=tan^{-1}(\frac{6}{4})\]
soo for sine, how would i put the equation in my calculator to find the missing angles?
for sine, you would need to know the length of the hypotenuse
ohhh okay
if we call the hypot "c"; then the law of sines is\[\frac{sin(90)}{c}=\frac{sin(\alpha)}{4}=\frac{sin(\beta)}{6}\] at any rate, to use sines we would have to determine the value of c
|dw:1347899040168:dw| now how do i use sine for this one?
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