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Mathematics 8 Online
OpenStudy (anonymous):

Could I find the two missing angle measures if I know some of the side lengths of a right triangle?

OpenStudy (amistre64):

yes

OpenStudy (amistre64):

you would need to know at least 2 side lengths

OpenStudy (anonymous):

how would i find this?

OpenStudy (amistre64):

by using the appropriate definitions for sine, cosine, and tangent

OpenStudy (amistre64):

or, by using the law of sines, in which case, youd still need to know about sines :)

OpenStudy (anonymous):

if two of my right triangle's side lengths were 4 and 6. i already know one angle is 90 degrees. so to find the others i would need to use sines?

OpenStudy (amistre64):

can you draw a picture and label it using the draw tool?

OpenStudy (anonymous):

|dw:1347897696371:dw| hope this helps.

OpenStudy (anonymous):

remember, we are trying to find the missing angle measures of this right triangle

OpenStudy (amistre64):

had to step away for a minute ...knowing tangent would be useful then

OpenStudy (amistre64):

|dw:1347898372808:dw|\[tan = \frac{opposite}{next.to}\]

OpenStudy (amistre64):

\[tan(\alpha)=\frac{4}{6}~:~\alpha=tan^{-1}(\frac{4}{6})\] \[tan(\beta)=\frac{6}{4}~:~\beta=tan^{-1}(\frac{6}{4})\]

OpenStudy (anonymous):

soo for sine, how would i put the equation in my calculator to find the missing angles?

OpenStudy (amistre64):

for sine, you would need to know the length of the hypotenuse

OpenStudy (anonymous):

ohhh okay

OpenStudy (amistre64):

if we call the hypot "c"; then the law of sines is\[\frac{sin(90)}{c}=\frac{sin(\alpha)}{4}=\frac{sin(\beta)}{6}\] at any rate, to use sines we would have to determine the value of c

OpenStudy (anonymous):

|dw:1347899040168:dw| now how do i use sine for this one?

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