Solve the equation. Check for extraneous solutions. 2|7-7x| = 2x+4
divide be 2 first to get the absolute by itself
What do I divide? the 7 by 2?
divide the left side by 2 and teh right side by 2. This will get rid of the 2 on the left and simplify the right
\[\left| 7-7x \right|=x+2\]
And then do I cancel the x's out?
7-7x is the agruement and it can equal +(x+2) or -(x+2)
not yet..
Do you understand my statement just now
I kinda do, a little bit is still confusing
what is inside the absolute value symbol whether positive or negative comes out positive right?
so the expression is saying that whatever 7-7x is it can be the positive or negative of x+2
So I take 7 & divide it by 2? Sorry I'm a little lost
you need to set 7-7x=x+2 and solve for x as well as set 7-7x=-x-2 and solve for x
This gets you both of your solutions
treat the absolute value signs as ( )
Would it be 3/2 & 5/8?
\[\frac{ 2\left| 7-7x \right| }{ 2 }=\frac{ 2x+4 }{ 2 }\]
see how the 2 cancels from the left and the right becomes x+2??
I havent solved it yet, hold on
ya I got the same
Alright I think I got the hang of it now thanks! (=
yup
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