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3 5/9 – 1 3/9 A. 4 2/9 B. 4 1/9 C. 2 1/9 D. 2 2/9
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You have 3 (integer) in the first and 1(integer) in the second, what can you do with them?
i don't know i am terribly bad at math
Think like if you had 3 things and a bit more, and you take 1 of them and a little bit more, but less than the bit you had first. How many things will you have?
|dw:1347914916859:dw|
Well you first have to learn how to convert \(3 {5 \over 9 } \) to a fraction.
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Here we have 3 and 5/9
|dw:1347927205191:dw|
lets look at the "3" first
ok
we need to change "3" to \(? \over 9\)
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well 1 is the same as \(9 \over 9 \)
would you agree with that?
Yes
so 2 would be 18/9
do you see how I got that?
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you divided..?
no
|dw:1347927458627:dw|
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