Question

Simplify: \[\sqrt{x ^{2}-16} + \frac{ x^2 }{x^2+1 }\]

Answer 1

https://www.google.com/search?q=(x-16)+%2B+x%5E2%2Fx%5E2%2B1&rlz=1C1CHFA_enUS484US486&sugexp=chrome,mod=18&sourceid=chrome&ie=UTF-8

Answer 2

x=-14

Answer 3

\[\sqrt{x ^{2}-16} + \frac{ x^2 }{x^2+1 }\]

Answer 4

If this is Calculus, then as X approaches larger numbers the square root of a number squared is that number (the -16 becomes insignificant). A number divided by itself is always one (again the plus one is insignificant). So the answer would be X as X approaches infinity.