On January 1, 2010, Chessville has a population of 50,000 people. Chessville then enter a period of population growth. Its population increases 7% each year. On the same day, Checkersville has a population of 70,000 people. Checkersville starts to experience a population decline. Its population decreases 4% each year. During what year will the population of Chessville first exceed that of Checkersville? Please show your work and explain your steps in the simplest way possible. :)

Question

anonymous · Answer

50,000(1.07)^t = 70,000(1-.04)^t = 70,000(.96)^t
(1.07/.96)^t=(70,000/50,000)=1.4
t ln (1.07/.96) = ln(1.4)
.10848 t = .33647
t=3.102

So population will be equal in 3.102 years

anonymous · Answer

Wow that was fast.

icalibear · Answer

Um can you explain what you just did please XD

anonymous · Answer

lol i googled it