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OpenStudy (anonymous):
A 135-g sample of a metal requires 2.50kj to change its temperature from 19.5 degrees Celsius to 100.0 degrees Celsius. What is the specific heat of this metal?
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OpenStudy (anonymous):
Q = m cp dT so cp would be: cp = Q/m dT where Q is heat, m is mass and dT is change in temperature (T2 - T1)
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