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Mathematics 7 Online
OpenStudy (anonymous):

How do I simplify this problem?

OpenStudy (anonymous):

You know it is quite rude to close out a question when someone is explaining something......

OpenStudy (anonymous):

\[\frac{ d ^{2} - d - 30 }{ d ^{2} +3d - 40 } + \frac{ d ^{2} +14d +48 }{ d ^{2} - 2d - 48 }\]

OpenStudy (anonymous):

Sorry, I just gave up on it

OpenStudy (anonymous):

the method I posted, you can go back and read it......

OpenStudy (anonymous):

Alright

OpenStudy (anonymous):

You need to factor each polynomial

OpenStudy (anonymous):

Think about the products that equal the last term and when added equal the center term

OpenStudy (anonymous):

I look at the center term first. So the numerator of the first fraction the center term is negative -1. So the 2 numbers are 1 apart and the negative goes the the higher number.

OpenStudy (anonymous):

How do I factor them, just find the gcf?

OpenStudy (anonymous):

Ah I'm confused

OpenStudy (anonymous):

\[\frac{ (x+5)(x-6) }{ (x+8)(x-5)}\]

OpenStudy (anonymous):

That is the first one factored

OpenStudy (anonymous):

Let's do the 2nd together. take the numerator first. What is the coefficient of the center term?

OpenStudy (anonymous):

14

OpenStudy (anonymous):

ok, so now lets look at the last term. What are the numbers when multiplied will equal 48?

OpenStudy (anonymous):

1,48 2,24 3,16, 4,12 6,8 and then make all of those negative

OpenStudy (anonymous):

so we need to look at these numbers and find the ones when added give us +14

OpenStudy (anonymous):

How do we figure that out?

OpenStudy (anonymous):

Patterns to recognize...\[(x ^{2}+2x+1)\]if there are 2 "+" then it must be in the form (x+n)(x+n)\[(x ^{2}-2x+1)\]if there is a "-" then "+" the form must be (x-n)(x-n)\[(x ^{2}+2x-4)or(x ^{2}-2x-4)\]If you see the above form then the factor is (x-n)(x+n)

OpenStudy (anonymous):

Add the numbers together that I separated with a comma. whatever equals 14 is what you need. Then follow the correct pattern above.

OpenStudy (anonymous):

So 6 & 8

OpenStudy (anonymous):

now write it according to the pattens I posted

OpenStudy (anonymous):

So where the 2 is I put 6, or is where the x's are where I put it?

OpenStudy (anonymous):

you need to replace n with the correct numbers

OpenStudy (anonymous):

So (x+6)(x+8)

OpenStudy (anonymous):

ya. follow these steps for each polynomial and see what you can simplify. sometimes you can get the same ( ) on the top and bottom and they cancel. I have to go. good luck

OpenStudy (anonymous):

Alright thanks for the help so far!

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