Question

writing a system of equations that has each ordered pair as its solution? (ex: 5,4)

Answer 1

x=5
y=4

so make up two random expression such as

x+y
or
3x-4y

then solve them both
and put them in the form
Ax+By=c

Answer 2

needs to be 2 separate equations.

Answer 3

x+y=?
x-y=?

Answer 4

yess..but how do i go from (5,4) to 2 different equations.

Answer 5

answer the dang question and you'll find out

Answer 6

all i am given is "write a system of linear equations that has a order pair of (5,4)" .

Answer 7

given (5,4)
meaning
x= 5
y=4
x+y=?
x-y=?

Answer 8

uhh that's definitely not it. i know that for sure. but thanks..

Answer 9

x+y=5+4=?????

x-y=5-4=??????

Answer 10

you're not being clear..haha

Answer 11

UGGGGGGG

ill telling showing you how would would create a system of equations.........

first you have a coordinate point (5,4)

coordinate points come in the form of (x,y)
thus
x=5
y=4

in order to get a system of equation with only these points as a solution

you need to create 2 equations that when you substitute these values into the equation will make it true

system of equations usually come in the form of
Ax+By=C

where A, B, and C are constants
you can make up random values for A and B,
C can solved when you substitute x and y into the equation

example, if A=1 and B=1
then i will get
x+y=C
now i solve for C
5+4=C
C=9
thus meaning one of the equations for the system of equations can be
x+y=9

now you need to create a 2nd equation that is true when you substitute in x and y

in this case, i chose A=1 and B=-1
x-y=C

finish it......

Answer 12

chill yourself. mahhh goodness. not my fault what you're saying doesn't make sense when, i know this much, theres gotta be numbers infront of x and/or y, not x+y equalying 9. get my drift?

Answer 13

there are numbers infront of x and y

1 is a number

if you dont like 1, then use 2
all i gave was an example