Question

(square soot of -2)(square root of 2)+(square root of -4i)- 2i^6+(square root of -2i^2)

Answer 1

\[\sqrt{-2}\sqrt{2}+\sqrt{-4i}-2i ^{6}+\sqrt{-2i ^{2}}\]??

Answer 2

yes

Answer 3

are you just supposed to simplify

Answer 4

yes, the sqare roots of -2 and 2 i dnt know how to do

Answer 5

Ok. I'll give it a launching off point

Answer 6

\[\sqrt{(-1)(2)}\rightarrow \sqrt{-1}\sqrt{2}\rightarrow i \sqrt{2}\rightarrow so \rightarrow i \sqrt{2}\sqrt{2}\]

Answer 7

can you see that the you will then end up with 2i

Answer 8

thts for both sqaure roots?

Answer 9

the first part is for the negative. After the so I included the positive root. I was just doing one at a time. Thats only for the first term. Do you know how to do the remaining terms?

Answer 10

i see...

Answer 11

can you wait a sec, please

Answer 12

sqaure root of -4i is \[i \sqrt{2i}\]

Answer 13

?

Answer 14

\[2i \sqrt{i}\]

Answer 15

-2i^=2.. so that +2

Answer 16

yup

Answer 17

+ \[i \sqrt{2}\]

Answer 18

?

Answer 19

do \[i ^{2}\]first, try again.

Answer 20

+\[\sqrt{2}\]?

Answer 21

yup. I don't think you can simplify it anymore from here. good job. I just ask if you could give me a medal. Makes me more reputable.

Answer 22

sure, thanks alot

Answer 23

where do i go to?

Answer 24

:)