Question

limits involving infinity....

Answer 1

\[g(x)= 1/8-(5/x ^{2}) a. x \rightarrow \infty b. x \rightarrow -\]

Answer 2

er? where's the limits?

Answer 3

find the limit of each function as x goes to +/- infinity

Answer 4

\[\lim_{x \rightarrow \infty}\frac{1}{8}−\frac{5}{x^2}\]

\[\lim_{x \rightarrow -\infty}\frac{1}{8}−\frac{5}{x^2}\]

Answer 5

do I first separate the equation? why is there no 1 in the numerator of the 5/x^2?

Answer 6

remember

\[\lim_{x \rightarrow \infty}\frac{1}{x}=0\]

\[\lim_{x \rightarrow \infty}\frac{1}{x^2}=0\]

Answer 7

1/8-0? =1/8

Answer 8

looks like it

Answer 9

okay..thank you

Answer 10

i must add
\[\frac{5}{x^2}=5*\frac{1}{x^2}\]

Answer 11

So, 1/8-0*5(0)=1/8?

Answer 12

are you asking a question, or just confirming

the limits just equal 1/8 because you're subtracting 0

Answer 13

just confirming