Find the solution set of the equation: (See below)
\[|\frac{ x-7 }{ 2 }|+8=8\]
take 8 from both sides
there is only one solution
So how would I get rid of the fraction inside of the brackets so that I could solve for x?
\[\left|\frac{x-7}{2}\right|=0\]
Right I got that. Sow how would that be expressed in interval notation if left like that?
for what values of x is the equation satisfied ?
dont leave it like that the only solution is x=somenumber
\[\left|\frac{x-7}{2}\right|=0\]\[\frac{\left|x-7\right|}{\left|2\right|}=0\]\[\frac{\left|x-7\right|}{2}=0\]\[\left|x-7\right|=0\]
How did you cancel the 2?
\[\frac{\left|x-7\right|}{2}=0\] \[2\times\frac{\left|x-7\right|}{2}=2\times0\] \[\left|x-7\right|=0\]
So you just cross canceled by multiplying both sides by 2?
exactly
So then I take that problem and come up with my solution set of (0,7)?
I got it {7}. Thanks!
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