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how to simplify this log stuff?
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\[\log_{1/4} (\sqrt[3]{32})\]
first can u write \(\sqrt[3]{32} \) as \((2^5)^{1/3}\)??
yes and?
use the property \(log a^n=nlog a\)
so u get \((5/3)log_{1/4}2\) got this ?
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i have to simplify to an exact number
oh, that was just intermediate step, its not finished yet, i was just asking whether u understood how i got that.....
then use the log property that: \(\large log_ab=\frac{log b}{log a}\)
so u get \((5/3)\frac{log 2 }{log 1/4}\) and since \(1/4 = 2^{-2}\) \(\huge(5/3)\frac{log 2 }{log 2^{-2}}\) can u simplify the denominator now ?
wow u are really a super saiyan
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u got the answer ?
ye thx
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