Question

Find the equation of the tangent to the graph at the indicated point.
f(x) = x2 − 3; a = 9
Y=

Answer 1

[f(x) = x^2 − 3
f'(x) =lim [(x+h)^2-3 - (x^2 − 3)]/h
h=>0
f'(x) =lim [(x^2+2xh+h^2-3) - (x^2 − 3)]/h
h=>0
f'(x) =lim [(x^2+2xh+h^2-3) - x^2 + 3)]/h
h=>0
f'(x) =lim [(2xh+h^2)]/h
h=>0
f'(x) =lim [(2x+h)]
h=>0
f'(x) = [(2x+0)]
f'(x) = 2x now at point a=9
f'(9) = 2(9)=18 .....ans

Answer 2

ok thnx,n gud luck

Answer 3

No thanks you!!