Question

What's the range for f(x)=4/(x^2-3x)

Answer 1

http://gyazo.com/639abde5d6c93ade3cc255f688ffa849

Answer 2

What are all the possible y values that could come from that function?

Answer 3

or one can find the domain of inverse

Answer 4

But can not find the inverse

Answer 5

what @mukushla said. probably the best bet

Answer 6

do you loose some values?
Domain of inverse:
http://www.wolframalpha.com/input/?i=domain+of+f%28x%29%3D%28x^2-3x%29%2F4

Range of function:
http://www.wolframalpha.com/input/?i=range+of+f%28x%29%3D4%2F%28x^2-3x%29

Answer 7

wrong function

Answer 8

\[f(x)=\frac{4}{x^2-3x}\]

Answer 9

if you want to use wolfram and not compute by hand, it is this one
http://www.wolframalpha.com/input/?i=range+f%28x%29%3D \frac{4}{x^2-3x}

Answer 10

which i guess requires copy and paste

Answer 11

what about the inverse?

Answer 12

or you can take
\[y=\frac{4}{x^2-3x}\] and solve for \(x\) to see what you get, as @mukushla suggested
that will give you the range

Answer 13

ohhh

Answer 14

@eyust707 mukushia means inverse function, not reciprocal
in other words solve for \(x\)

Answer 15

got it! thx for the explanation!

Answer 16

yw, hope whoever asked also knows what to do

Answer 17

I got it. I figured out the inverse function by using quadratic formula, and found out the range for it.
Thanks everybody.

Answer 18

very well :)

Answer 19

that is the right thing to do
you get a radical, make sure the discriminant is \(\geq 0\)