Given a 60-μC point charge located at origin. find total electric flux passing through:

a) that portion of the sphere r=26 cm bounded by and

b) the close surface defined by ρ = 26 cm and z = ±26 cm

c) the plane z = 26 cm

Question

﻿Given a 60-μC point charge located at origin. find total electric flux passing through:

a) that portion of the sphere r=26 cm bounded by and

b) the close surface defined by ρ = 26 cm and z = ±26 cm

c) the plane z = 26 cm

anonymous · Answer

for my first part it like that as we all know that flux density is the charge per unt area here charge is 60uc so divide 60uc by (4*pi*r2) we get  D= 7.06*10^-5 c/m2.
NOW given is portion with r=26cm theta= 0 to pi/2 and phi = 0 to pi/2
calculate required region area with formula =double integral(r^2sintheta dtheta dphi)
we get =.106m^2 now multiply  D*Required region we get 7.5uc M I RIGHT PLZ tell me

anonymous · Answer

but i am confused in b and c part how to calculate area of a plane z=26cm. pz reply as soon as possible

anonymous · Answer

plz send answer to my mail id= engg.akd@gmail.com