After being shot from a cannon, he soared over three Ferris wheels and into a net (see the figure). Assume that he is launched with a speed of 26 m/s and at an angle of 50°. (a) Treating him as a particle, calculate his clearance over the first wheel. (b) If he reached maximum height over the middle wheel, by how much did he clear it? (c) How far from the cannon should the net's center have been positioned ? Distance from 1st ferris wheel is 21 m. Height of the net and launch height are 3 m. Wheel height 15m. I need help with finding answers for A and B, please!

Question

anonymous · Answer

I have the total range to the net as 67.93 meters, using the following equation:

$$R=(2v _{o}^{2}/g)(\sin2\theta)$$

anonymous · Answer

It seems like the problem in Halliday's book :)
I think you quite understand this problem. Which part do you want to ask?

anonymous · Answer

You're correct. I'm having truble with find the vertical heights.

anonymous · Answer

$$v^2=v_0^2-2gh$$
You can find h max from that equation right?

anonymous · Answer

I think so. re arrange for h, correct?

anonymous · Answer

max height is when the object isnt moving at all, right?

anonymous · Answer

It's y component of velocity is zero. It still move, in x direction :)

anonymous · Answer

Just need help on the answer for A now.

jfraser · Answer

you know the distance from the cannon to the first wheel. You also know how tall the wheel is. You need to find how high he will be when he's directly over the first wheel.

You need to find the time needed to travel (in the x-direction) the 21m to get to the first wheel. Using that time, find out his y-position. Find the difference between his height @21m and the height of the wheel.