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Use your knowledge of the derivative to compute the limit given below lim h→0 ((x+h)^−2.25)−(x^−2.25)/h.
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\[\lim_{h \to 0} {(x + h)^{-2.25} - (x^{-2.25}) \over h}\]Notice that this is actually the derivative of nothing, but \(x^{-2.25}\). Use the power rule to simplify the rest.
Why is this the derivative of \(x^{-2.25}\)? The definition of a derivative says that,\[f'(x) = \lim_{h \to0} {f(x + h) - f(x) \over h}\]So, \(f(x) = x^{-2.25}\) after comparing the above definition with your question. And we have to find \({d \over dx}x^{-2.25}\).
The rest should be very easy for you.
yes i understand now thank you so much!
You're welcome :)
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