Question

Find the equation of the normal to the curve y = 3x^2-2x-1 which parellel to the line y = x-3

Answer 1

@sauravshakya @TuringTest @satellite73

Answer 2

find y', set it equal to -1 and solve for x; that's an x coord. on your line.
plug into y = 3x^2-2x-1to get a y coord. you have a point and the slope now.. find the line?

Answer 3

1º. Find the derivative of y
2º Put it in some form you like (slope intercept, general...)
3º change it's direction vector to perpendicular
4º find x, for which it's slope is 1

Answer 4

i got the points, why is the slope 1, it has to be -1 since we take the normal line?

Answer 5

if slope of the tangent = -1, slope of the normal =1.

Answer 6

can u show it in a diagram?

Answer 7

i cant picture the problem clearly?

Answer 8

@Algebraic! where the parellel like y=x-3?

Answer 9

wut

Answer 10

can u show the parellel line y =x-3 in the diagram?