the formation of solid argon is due to van der waal's bonding.In the case of potential energy as a function of inter-atomic separations can be written as(lennard johnes 6-12 potential energy)e(r)=-ar^-6+b^-12 where 'a' and 'b' are constants a=8.0*10^77jm^6and b=1.12*10^-133jm^12,the bond length for solid argon is:
a)3.75nm
b)0.0375nm
c)0.375nm
d)0.750nm
which is correction and how with solution?

Question

the formation of solid argon is due to van der waal's bonding.In the case of potential energy as a function of inter-atomic separations can be written as(lennard johnes 6-12 potential energy)e(r)=-ar^-6+b^-12 where 'a' and 'b' are constants a=8.0*10^77jm^6and b=1.12*10^-133jm^12,the bond length for solid argon is:
a)3.75nm
b)0.0375nm
c)0.375nm
d)0.750nm
which is correction and how with solution?

anonymous · Answer

The bond length will where the potential energy is lowest.  So take the derivative with respect to r of the Lennard-Jones function, set it equal to zero, solve for r.