The ball leaves Sarah's hand a distance 1.5 meters above the ground, and is moving with a speed of 8.0 m/s when it reaches a maximum height of 13.0 m above the ground.
What is the speed of the ball when it leaves Sarah's hand?

Question

The ball leaves Sarah's hand a distance 1.5 meters above the ground, and is moving with a speed of 8.0 m/s when it reaches a maximum height of 13.0 m above the ground. 
What is the speed of the ball when it leaves Sarah's hand?

anonymous · Answer

the fact that it's moving at its highest point means that the x velocity is 8 m/s (because vertical velocity is zero at that point)
you can find Vyi from   Vyf^2 = Vyi^2 -2*g*11.5m    (where Vfy is going to be zero)
calculate initial speed from the two components of initial velocity we just found
|Vi| = sqrt ( Vyi^2 +Vix^2)

anonymous · Answer

thank you! How high above the ground will the ball be when it gets to Julie? (note, the ball may go over Julie's head.)

anonymous · Answer

no idea.

anonymous · Answer

ok thank you so much though u really helped me!

anonymous · Answer

sure:)