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Mathematics 16 Online
OpenStudy (anonymous):

Find a member of the family that is a solution of the initial-value problem:

OpenStudy (anonymous):

\[y = c_{1}e ^{x} + c _{2}e ^{-x}, (-\infty, \infty);\] \[y \prime \prime - y = 0, y(0) = 0, y \prime(0) = 1\]

OpenStudy (turingtest):

they just want you to find c1 and c2 have you never done this before?

OpenStudy (turingtest):

oh wait, a double derivative and only single condition...

OpenStudy (anonymous):

Well, I kinda skipped this section in class. I can find general solutions, but the wording here throws me

OpenStudy (turingtest):

still though, it should work...

OpenStudy (anonymous):

so what just plug in values and take integrals?

OpenStudy (turingtest):

plug in the conditios given y(0)=? you will get an equation y'(0)=? you will get another equation two equations with two unknowns; solve the system for the unknowns

OpenStudy (anonymous):

so is all that find the member family talk just find the values of c1 and c2?

OpenStudy (turingtest):

the value of c1 and c2 you get (which depends on the initial conditions) determines which "member of the family", so to speak, is the answer you are searching for by leaving c1 and c2 as unknown, it is general (the whole family) by using initial condition to find c1 and c2 you have found a specific solution ( a member of the family)

OpenStudy (turingtest):

so the problem is asking you to use the initial conditions to find c1 and c2, which will tell you which member of the family of integral curves is the solution to our IVP

OpenStudy (anonymous):

So is this similar to finding the particular solution of a differential equation, or something totally different?

OpenStudy (turingtest):

ok let me double-check my terminology...

OpenStudy (turingtest):

yes, as I suspected the terminology is a bit tricky here the "particular solution" from a non-homogeneous equation found through things like undetermined coefficients and such) is not to be confused with the solution to out initial value problem, in which we identify the values of c1 and c2 to determine which integral curve we are talking about I know of no other term for "the integral curve" or "member of the solution family" for what I am referring to, but the "particular solution to a non-homogeneous equation" is a very different thing.

OpenStudy (anonymous):

awesome, you are a champ. Im going to try out just solving. Thanks a bunch for the clarity.

OpenStudy (turingtest):

very welcome :)

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