How do you know if a limit is going to be zero when x is approaching infinity?
if the denominator of a fraction is increasing at a faster rate than the numerator.
what do you mean by increasing at a faster rate?
for example: x/x^2 approaches 0 as x approaches infinity, because x approaches infinity slower than x^2
Example: 1/1 = 1 2/4 = 0.5 3/9 = 0.333.... 4/16 = 0.25 5/25 = 0.2 6/36 = 0.166..
See, the bottom increases faster than the top.. The example above was for x/x^2
So if you keep going: 1,000,000/1,000,000,000,000 = 0.000001
ohhhh i see. so if it is (e^x)/(x^2), the limit would be zero?
no, the limit would be infinity. e^x increases faster than x^2
oh whoops
e=2.71 x=1 e^2 = something like 5 or 6 2^2 would be 4
So the one you gave would go off to infinity.
anything to the x increases faster than x to some constant power.
as x goes to infinity.
so lnx/(e^x) would have a limit of zero right
yes
ohhhh okay. thanksss
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