Question

Solve using intervals: (x+3)(x-2) > 0

Answer 1

(x+3) and (x-2) > 0

Next,

x = -3
x = +2

Since x = 2 is greater, write it as greater:
x>2

AND, x = -3 is smaller,
x < -3

Answer 2

Thankyou ! :)

Answer 3

when you say " Since x = 2 is greater, write it as greater" do you mean greater than the other value or what ? @saifoo.khan

Answer 4

Yes, greater than the other value.

Answer 5

(which was -3)

Answer 6

but i dont understand that.. for this example (x-6)(x-9) <0
x<6 and x<9 .. whyyy though ?!

Answer 7

Right, that was something i was looking for..

Answer 8

Whenever you have a < or <= sign,
write a combines inequality

Whenever you have a > or >= sign,
write the > with bigger root and < with smaller root.

Answer 9

but how will you know if they're the same

Answer 10

If the roots are:
(x+3)(x+3) > 0
then,
x > 3, x < -3

-------------------

If the roots are:
(x+3)(x+3) < 0
then,
no roots exists.

Answer 11

no what im asking is (x-6)(x-9) <0
is x<6 and x<9

i dont understand how that works out, they both have the same sign

Answer 12

from 6 and 9, which one's lesser?
6 right?

Answer 13

yes

Answer 14

So,
6 < x < 9

Answer 15

ohh yup okay i think i got it

Answer 16

(x+3)(x+5) > 0 would be -3>x>-5 ?

Answer 17

No, now look there's a GREATER sign!

Answer 18

but isn't -3 a greater value than -5

Answer 19

Sure it is.

Answer 20

this is the question and solution
i'm still very confused lol :(

Answer 21

Case 1
Whenever you have a < or <= sign,
write a combines inequality

Case 2
Whenever you have a > or >= sign,
write the > with bigger root and < with smaller root.

Answer 22

Here, we will use case 2