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calculus: f(x)=(sin(x+1)/(x+1). does it have a vertical asymptote or a removeable discontinuity at x=-1??
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Well, how do you think you should start this problem?
well my main concern is idk if you can cancel the x+1 out
Of course you can't. Find the limits manually.
Or, you can use l'hopital's rule given that you have learned it.
cannot cancel because it is not the exact same!!!
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and, here's a hint: sin(a+b)=sin(a)cos(b)+sin(b)cos(a)
oh ok so it has vertical asymp?
Find the left and right hand limits. Are they the same?
\[\lim_{x \rightarrow -1^-}=\lim_{x \rightarrow -1^+}\] is what I'm asking here.
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