Solve the quadratic equation by using the square root property:

(2x-4)^2 = 13

Question

Solve the quadratic equation by using the square root property:

(2x-4)^2 = 13

anonymous · Answer

(2x-4)(2x-4)= 13
4x2 - 8x - 8x +16= 13

anonymous · Answer

So now you just have to simplify.

anonymous · Answer

4x2-16x+3= y, 
I suppose you also want the roots of this equation?

valpey · Answer

$$(2x-4)^2=13$$Take square roots of both sides$$\sqrt{(2x-4)^2}=\pm\sqrt{13}$$$$(2x-4)=\pm\sqrt{13}$$Add 4 to both sides$$2x=4\pm\sqrt{13}$$Divide both sides by 2.

anonymous · Answer

Woops, hes right, I didnt use the square root property

anonymous · Answer

Valpey, I've tried entering in 2 +/- sqrt(13) several times, and the program says it's wrong. 
And yes, Ren, I do.

anonymous · Answer

Sorry...+/-sqrt(13/2)

valpey · Answer

@Ren is helping you convert this into the classic form of the quadratic equation. I don't think you need to do that.

@Mbrecht Not sqrt(13/2) but sqrt(13)/2

valpey · Answer

$$x=2\pm\frac{\sqrt{13}}{2}$$

anonymous · Answer

No, I don't think I do. I seem to recall trying that as well, but I'll give it another spin.

anonymous · Answer

Are you entering both + and minus equations separately?

anonymous · Answer

No, I apparently hadn't...lol. Thank you both a tremendous amount.

valpey · Answer

Cheers.