Question

I need help with an algebra problem! Anyone?

Answer 1

yes

Answer 2

Okay, wonderful. So, here it is:

Find the values of x satisfying the given conditions.

y1 = 2x/x+3, y2 = 3/x+5 and y1 + y2 = 1.

Answer 3

2x/(x+3) + 3/(x+5) = 1
get a common denominator 2x(x+5)/((x+5)(x+3) + 3(x+3)/(x+5)(x+3) =1
simplify
2x(x+5)+3(x+5)/(x+5)(x+3) = 1
distribute and simplify: 2x^2+13x+15/x^2+8x+15 =1

Answer 4

2x^2+13x+15=x^2+8x+15
subtract 15 from both sides and set equal to zero: x^2+5x=0
x(x+5)=0
x=0, -5

Answer 5

Um...the program says that 0, -5 is incorrect.

Answer 6

Are you sure you approached the problem the right way?

Answer 7

wait a sec let me do it on paper real fast

Answer 8

Everybody else: This is the problem:

Find the values of x satisfying the given conditions. y1 = 2x/x+3, y2 = 3/x+5 and y1 + y2 = 1.