find y in terms of x when log2y=2+log2x
do you know how to change log_2 y = 2 + log_2 x into exponential form?
need to find y in terms of x when log2y=2+log2x
did you ask me a question? It's my first time here, so I'm not familiar with right steps to follow
do you know how to change log_2 y = 2 + log_2 x into exponential form?
i'm asking if you know how to start
..how to start solving the problem
wouldn't yo uconvert this to exponential form, so y=2^(2+log2x)?
right
now.. are you familiar with this concept: \[\huge a^b \times a^c = a^{b+ c}\]
yes
good. so can you apply that in 2^(2+ log_2 x)
could you convert the log_2 x into exponential form also?
tell me what you got for 2^(2+log_2 x) first
i'm not entirely sure on that one
use the property a^(b+c) = a^b * a^c
okay well than it should be (2^2)*(2^log_2 x)
right
now here comes another property \[\huge a^{\log_a b} = b\] do you understand what that means?
yes - does that mean that the answer to this question would be 4x?
right. but the complete answer is y = 4x
because you want the expression in terms of y
alright, that makes sense - thanks a lot for the help!
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no. it's very free
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