(9m)^-2
Simplify. Using positive exponents only.
Help please?
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OpenStudy (lgbasallote):
9m - 2 is already in simplest form....
OpenStudy (anonymous):
well it's actualy (9m)^2
OpenStudy (anonymous):
sorry i mean (9m)^-2
OpenStudy (anonymous):
its asking me to use postive exponents only. I am confused.
OpenStudy (lgbasallote):
here's a hint \[\huge a^{-m} \implies \frac 1{a^m}\]
does that help?
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OpenStudy (anonymous):
is it 18m?
OpenStudy (anonymous):
i mean 81m
OpenStudy (lgbasallote):
how did you get that?
OpenStudy (anonymous):
exponents really confuse me alot
OpenStudy (lgbasallote):
let me give an example \[\huge 2^{-2} \implies \frac 1{2^2} \implies \frac 14\]
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OpenStudy (lgbasallote):
do you get it now?
OpenStudy (anonymous):
9m*2? am I on the right track?
OpenStudy (lgbasallote):
no...
OpenStudy (anonymous):
:(
OpenStudy (lgbasallote):
let me give another example \[\huge (3x)^{-2} \implies \frac 1{(3x)^2} \implies \frac 1{9x^2}\]
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OpenStudy (anonymous):
would you mind showing me the steps? I am a first year algebra student and have no idea what I am supposed to be doing. Sorry that I am not getting your examples.
OpenStudy (lgbasallote):
like i said before...if you have a negative exponent..just put it in the denominator for example (3x)^(-2)
to make the exponent positive, all you have to do is put it in the denominator like so \[\frac{1}{(3x)^2}\]
follow?
OpenStudy (anonymous):
sort of, yes.
OpenStudy (anonymous):
so 1/(9m)^2 = 1/9m^2?
OpenStudy (lgbasallote):
no.. you have to square 9 as well
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OpenStudy (lgbasallote):
see what i did earlier \[\frac 1{(3x)^2} \implies \frac 1{3^2 x^2} \implies \frac 1{9x^2}\]