(9m)^-2 Simplify. Using positive exponents only. Help please?
9m - 2 is already in simplest form....
well it's actualy (9m)^2
sorry i mean (9m)^-2
its asking me to use postive exponents only. I am confused.
here's a hint \[\huge a^{-m} \implies \frac 1{a^m}\] does that help?
is it 18m?
i mean 81m
how did you get that?
exponents really confuse me alot
let me give an example \[\huge 2^{-2} \implies \frac 1{2^2} \implies \frac 14\]
do you get it now?
9m*2? am I on the right track?
no...
:(
let me give another example \[\huge (3x)^{-2} \implies \frac 1{(3x)^2} \implies \frac 1{9x^2}\]
would you mind showing me the steps? I am a first year algebra student and have no idea what I am supposed to be doing. Sorry that I am not getting your examples.
like i said before...if you have a negative exponent..just put it in the denominator for example (3x)^(-2) to make the exponent positive, all you have to do is put it in the denominator like so \[\frac{1}{(3x)^2}\] follow?
sort of, yes.
so 1/(9m)^2 = 1/9m^2?
no.. you have to square 9 as well
see what i did earlier \[\frac 1{(3x)^2} \implies \frac 1{3^2 x^2} \implies \frac 1{9x^2}\]
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