Question

find limit as x approaches infinity

sqrt. (x+3) / sqrt. (3x+1)

Answer 1

\[\lim_{x \rightarrow \infty}\frac{\sqrt{x+3}}{\sqrt{3x+1}}=\lim_{x \rightarrow \infty}\sqrt{\frac{x+3}{3x+1}}\]

Answer 2

now just look at the expression within the square root

\[\lim_{x \rightarrow \infty}\frac{{x+3}}{{3x+1}}\]

remember that it is all under a square root, so if the limit of that is negative, then there is no solution because you cant take the square root of a negative number

Answer 3

can you solve it now?

Answer 4

i thought it was 1/3
but it's not