Question

Forming a polynomial with degree 5 and with these zeros: -6,-i,-6+i.
Just need help being able to solve it please.

Answer 1

since the imaginary roots occur in conjugate pairs thus the 5 roots are as folllows
-6,-i,+i,-6+i,-6-i

Answer 2

thus the eq is of the form (x+6)(x+i)(x-i)(x+6-i)(x+6+i)=0
or (x+6)(x^2+1)(x^2+12x+37)=0

Answer 3

rest i hope u can multiply..

Answer 4

Thanks. I was wondering though if you can get the values as well by trying to use the quadratic formula?