Question

Which of the following compounds has a net dipole?
a. CH3CH2NHCH2CH3
b. CH3CH2CH2OH
c. FCH2CH2CH2F
d. Compounds (a) and (b) both have net dipoles
e.Compounds (a), (b), and (c) all have net dipoles.

Answer 1

My answer key says that e is the answer, but I'm confused... doesn't C have a net dipole of 0 since both flourines are pulling in opposing directions?

Answer 2

answer choice C*, not the element :p

Answer 3

Yes, C.

Answer 4

Thanks for the reply Sam... so does that mean that the answer key is wrong? (A.) has a net dipole because of the Nitrogen right, and I think (B.) does too because of the OH right?

Answer 5

You are correct.

Answer 6

thank you. Since you're around, can I ask you another question? I'm just reviewing a bunch of stuff.

question:
Given the pKa data, which of the following bases is(are) strong enough to deprotonate C6H5OH (pKa = 10) so that the equilibrium lies to the right?
Compound pKa
H3O+ –1.7
NH4+ 9.4
H2O 15.7
NH3 38

[1] NaOH
[2] NaNH2
[3] NH3
[4] Compounds 1 and 2 are strong enough to deprotonate C6H5OH.
[5] Compounds 1, 2, and 3 are all strong enough to deprotonate C6H5OH.

It's been a while since I did acid bases. All I seem to remember is that ph=-log[Ka] or something.