Question

A 1000 kg vehicle moving with a speed of a 20 m/s is brought to rest in a distance of 50 metre by applying brakes :


(i) Find the acceleration.


(ii) Calculate the unbalanced force acting on the vehicle.

Answer 1

@ash2326 @UnkleRhaukus @experimentX @hartnn

Answer 2

@.Sam. @sauravshakya

Answer 3

@pratu043 @ghazi

Answer 4

plz.........help me

Answer 5

so the acceleration is in opposite direction to movement

Answer 6

it is deceleration

Answer 7

ok!!!! then

Answer 8

v=u+at=0, find t from here
put it in s=ut+0.5at^2
find a

Answer 9

I think acceleration=\[(\frac{v-u}{t})\]

Answer 10

@hartnn but, i don't know acc.

Answer 11

F=m*a
v^2=2*a*s

Answer 12

here V=20

Answer 13

t=-20/a
put this in s=ut+0.5at^2

Answer 14

s=50,u=20

Answer 15

\[(20)^2= 2*a*50\]

Answer 16

then F= m*a

Answer 17

@ghazi u getting a=4, but a must be negative as it is deceleration..

Answer 18

@hartnn @experimentX i have considered V as initial velocity ....it's all about consideration :)

Answer 19

@mathslover

Answer 20

ok!! then, @experimentX

Answer 21

@mayankdevnani i guess just calculation is left

Answer 22

ok!! @ghazi

Answer 23

but, what's about a @experimentX

Answer 24

deceleration = \[4m/s^2\]

Answer 25

right... @ghazi

Answer 26

but how you can find it... @ghazi please tell me step by step....

Answer 27

then F= 1000*4 N it is called as unbalanced cuz...if forces would be balanced then either a=0 or net force = 0

Answer 28

yaa... f=4000N

Answer 29

but please tell me step by step

Answer 30

\[(20)^2=2*a*50......a =\frac{ 400 }{ 100 }=4\]

Answer 31

but, F=m*a
v^2=2*a*s
how can you find it

Answer 32

see from equation\[U^2=2*a*S\] we will have acceleration then use value of that acceleration in F=m*a to find F....since you've been provided with m=1000 and you have a=4 from above equation

Answer 33

@mayankdevnani does that help?

Answer 34

yaaaaa..... @ghazi

Answer 35

but, how can you find s

Answer 36

S=distance =50 m

Answer 37

m = 1000 kg

u = 20
v = 0
s = 50

v^2 - u^2 = 2a*50

-400 = 100 a

a = -4 m/s^2

F = 1000 kg * - 4 m/s^2 = -4000 N

Answer 38

that "-" MUST NOT BE NEGLECTED...

you can say that force = 4000 N in opposite directionn

Answer 39

*direction

Answer 40

or retarding force

Answer 41

@mathslover s=50 ??? where you got 50... please tell me @ghazi and @mathslover

Answer 42

@mayankdevnani it was given

Answer 43

Please see the question again

Answer 44

see the distance covered before vehicle comes to stop = 50 m = S it is given in your question

Answer 45

ya.... ok!!!! thanks a lot much thanks to @ghazi

Answer 46

:) YW

Answer 47

:( no problem ... sorry I was late but feel lucky to have answer by @ghass1978 :)

Answer 48

\[\huge{\color{blue}{\mathbb{Good}}\space \color{red}{\mathsf{Work}} \space \color{green}{\textbf{Ghazi}}}\]

Answer 49

Oh my KUDOS @mathslover sorry i am bad over latex lol

Answer 50

lol no problem ghazi .. enjoy that sweet KUDOS .. :)

Answer 51

:) thanks