Question

A 5 quintal car is moving with a velocity of 54 km/hr. What is its impulse if it is stopped within 0.5 s by application of backward force ? Also determine the force applied.

Answer 1

@ghazi @mathslover @experimentX @hartnn

Answer 2

\[impulse= \frac{ \delta force }{ \delta time }\]

Answer 3

no , impulse = force * time

Answer 4

find acceleration first

Answer 5

sorry for that

Answer 6

ok! left it.. what are say

Answer 7

V= 54km/hr= 54*5/18= 5*3m/s=15m/s

Answer 8

now again V= at
15=a*0.5
a=15/0.5=30m/s^2 (retardation)

Answer 9

hey.... 18= ??? where you got

Answer 10

now force= mass* a convert that mass into kilograms

Answer 11

but, 1 quintal = 100 kg

Answer 12

and then impulse = force* time , that is the short duration for which a huge force acted :)

Answer 13

then , @ghazi

Answer 14

force= 500*30=15000 N
and impulse= 15000*0.5= 7500 Ns

Answer 15

thnx..... @ghazi

Answer 16

:)

Answer 17

What is the relation between Impulse and Momentum.

Answer 18

an it be @ghazi
The Impulse is the change in momentum!
Momentum (Kg m/s) = mass x velocity
Impulase can also be worked out by the formula...
Impulse (Ns) = Force x Time

Answer 19

is that right?????? @ghazi

Answer 20

see momentum by newton's second law momentum= force/ time
and impulse = force *time
and you can see that higher the change in momentum lesser will be impulse
basically impulse is inversely proportional to momentum

Answer 21

clear?

Answer 22

ok clear.