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OpenStudy (anonymous):
question: Given the pKa data, which of the following bases is(are) strong enough to deprotonate C6H5OH (pKa = 10) so that the equilibrium lies to the right? Compound pKa H3O+ –1.7 NH4+ 9.4 H2O 15.7 NH3 38 Answer Choices [1] NaOH [2] NaNH2 [3] NH3 [4] Compounds 1 and 2 are strong enough to deprotonate C6H5OH. [5] Compounds 1, 2, and 3 are all strong enough to deprotonate C6H5OH. It's been a while since I did acid bases. All I seem to remember is that ph=-log[Ka] or something.
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OpenStudy (yash2651995):
pH= - log [H+]
OpenStudy (yash2651995):
Pka= - log ka
OpenStudy (yash2651995):
i guess, [5]
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