Given this function, find the domain and range, the x and y intercepts, the horizontal asymptote, and the vertical asymptote.
\[f(x)= \frac{ 2 }{ ^{x^2 - 2x - 3} }\]
range is \[x \in R - \left\{ 2 \right\}\left\{ 3 \right\}\]
domain is infinity
Thank you
Can you help me with the other things?
;)
which ones
The x and y intercepts, the horizontal asymptote, and the vertical asymptote
horizontal asymptote put x=0 vertical asymptote put y=0
actually those answers are not correct
in fact none of them are correct
you know midnight study leads to this :D sry
for the DOMAIN set the denominator equal to zero and solve then exclude those values \[x^2-2x-3=0\] \[(x-3)(x+1)=0\] \[x=3,x=-1\] so the domain is all numbers except \(3\) and \(-1\)
range is all real numbers except 0 because a fraction is only 0 if the numerators is 0, and your numerator is 2
vertical asymptote you already solved for, it is the zeros of the denominator \[x=3,x=-1\] horizontal asymptote is \(y=0\) because the degree of the numerator is less than the degree of the denominator
Thank you so much!
yw
Yes, I got that too :)
x intercept is when y=0
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