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how to change this recurring decimal into fractions. 0.9'
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let x = 0.9' 10x = 9.9' 9x = x =
in other words, if x= 0.9999..... and 10x= 9.9999..... what do you get if you subtract x from 10x 10x= 9.9999.... - x= - 0.99999.... ___________________ 9x= ??
.9 recurring as a fraction is 9/9 = 1 Any pure recurring decimal is just that number divided by 9, for example: .1 recurring is 1/9 .4 recurring is 4/9 In the case of .9 recurring it turns out that it's 1. There is a mathematical proof for this, but I don't have that remembered off the top of my head. Good Luck
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