Question

An acute angle θ is in a right triangle with sin θ = 6/7 . What is the value of cot θ

Answer 1

What have you tried till now?

Answer 2

Well,\[\tan \theta = {opposite \over adjacent}\]From \(\sin \theta\), we know that "opposite" is 6.

Answer 3

Also, you must must find the adjacent side through Pythagorean Theorem.\[6^2 + b^2 = 7^2\]

Answer 4

Yeah, also recall that\[\cot \theta = {adjacent \over opposite}\]

Answer 5

so thats right? :)

Answer 6

\[b = \sqrt{7^2 - 6^2} = \sqrt{13}\]Yay!

Answer 7

ohh so 6/√13 ?

Answer 8

No, your answer is right.

Answer 9

ok i gt confused for a seccc

Answer 10

love ur pic btw