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Mathematics 15 Online
OpenStudy (anonymous):

expand 2x^2+3x+1

Parth (parthkohli):

Already expanded. Do you want to factor?

OpenStudy (anonymous):

yes

Parth (parthkohli):

What have you tried till now?

OpenStudy (anonymous):

(2x-1) (3x+1)

OpenStudy (anonymous):

the factors of the last term need to add up to the middle term.

OpenStudy (anonymous):

You know that the first factors are not 2x and 3x since 2x*3x = 6x^2

OpenStudy (anonymous):

(2x+1) (x+2)

OpenStudy (anonymous):

The last terms, 1 and 2, when multiplied is 1*2 which equals 2. You are looking for +1

OpenStudy (anonymous):

Remember that when you are factoring you can always check your answer by expanding. With (2x +1)(x+2) you can multiply it out using FOIL (First, Outside, Inside, Last). First: 2x times x = 2x^2, so far so good. Outside: 2x times 2 = 4x Inside: 1 times x = x Last: 1 times 2 = 2. So, you end up with 2x^2 +4x+x+2 = 2x^2 +5x+2, not correct.

OpenStudy (anonymous):

I would use the quadratic for this one since it is hard to figure out the roots for this by factoring.

OpenStudy (anonymous):

lol at least for me

OpenStudy (anonymous):

I disagree @Nameless, factoring is the way to go here.

OpenStudy (anonymous):

show me the way :)

OpenStudy (anonymous):

(2x+1)(x+1) = 2x^2+2x+x+1 = 2x^2+3x+1

OpenStudy (anonymous):

You know that the first terms are 2x and x since you need 2x^2 You know that the last terms are either +1,+1 or -1,-1 since you need +1. Trial and error gives you +1,+1

OpenStudy (anonymous):

teic85 is right

OpenStudy (anonymous):

yep :) i was only saying the quadratic works better for me.

OpenStudy (anonymous):

agree.

OpenStudy (anonymous):

The quadratic works best because it will solve any quadratic equation. It's a failsafe. But, students need to know how to factor as well.

OpenStudy (anonymous):

thanks teic

OpenStudy (anonymous):

You're welcome! :)

OpenStudy (anonymous):

The best way to master these is to practice. You'll start to see patterns and begin to factor in your head.

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