expand 2x^2+3x+1
Already expanded. Do you want to factor?
yes
What have you tried till now?
(2x-1) (3x+1)
the factors of the last term need to add up to the middle term.
You know that the first factors are not 2x and 3x since 2x*3x = 6x^2
(2x+1) (x+2)
The last terms, 1 and 2, when multiplied is 1*2 which equals 2. You are looking for +1
Remember that when you are factoring you can always check your answer by expanding. With (2x +1)(x+2) you can multiply it out using FOIL (First, Outside, Inside, Last). First: 2x times x = 2x^2, so far so good. Outside: 2x times 2 = 4x Inside: 1 times x = x Last: 1 times 2 = 2. So, you end up with 2x^2 +4x+x+2 = 2x^2 +5x+2, not correct.
I would use the quadratic for this one since it is hard to figure out the roots for this by factoring.
lol at least for me
I disagree @Nameless, factoring is the way to go here.
show me the way :)
(2x+1)(x+1) = 2x^2+2x+x+1 = 2x^2+3x+1
You know that the first terms are 2x and x since you need 2x^2 You know that the last terms are either +1,+1 or -1,-1 since you need +1. Trial and error gives you +1,+1
teic85 is right
yep :) i was only saying the quadratic works better for me.
agree.
The quadratic works best because it will solve any quadratic equation. It's a failsafe. But, students need to know how to factor as well.
thanks teic
You're welcome! :)
The best way to master these is to practice. You'll start to see patterns and begin to factor in your head.
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