hey who can help with this:

(a+5)^3−(b−5)^3/ (a+5)^4−(b−5)^4
can be written as A/B where

A=
B=

Question

hey who can help with this:

(a+5)^3−(b−5)^3/ (a+5)^4−(b−5)^4
can be written as A/B where 

A=
B=

anonymous · Answer

anyone?

tyteen4a03 · Answer

The equation is $\frac{(a+5)^3−(b−5)^3} {(a+5)^4−(b−5)^4}$. Remember that $\frac {a^x} {a^y}$ = a ^ (x - y).

anonymous · Answer

It's also useful to know that A^3 - B^3 = (A - B)(A^2 + AB + B^2) and the difference of squares.

anonymous · Answer

good point! Thanks guys!

anonymous · Answer

You're welcome :)

anonymous · Answer

still confused as to how to utilize this to solve it

What would a^4-b^4 expand as?

anonymous · Answer

I utilized the rule  a^z/a^y = a ^ (x - y) previously and came down with a-b+10-

however, this cannot be the answer as the answer has to be in the form A/B :(

anonymous · Answer

It should expand as A^2 - B^2 = (A+B)(A-B), and A is in this case (a-5)^2 and B is (b-5)^2

anonymous · Answer

I apologize I switched the denominator and numerator

(a+5)^4−(b−5)^4/ (a+5)^3−(b−5)^3
can be written as A/B where

anonymous · Answer

Doesn't matter, just apply the transformations we discussed.