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A rectangular garden has a width of 5 feet and a length of 10 feet. If an equal amount is added to both the width and the length, the area is increased to 84 square feet. What is this amount?
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Let me see if i understand right? T = area, w = width, l = length, k = the constant amount. T = (w+k)*(l+k) 84 = (5 + k) * (10 + k) = k^2 + 15k + 50 0 = k^2+15k - 34 This is a quadratic equation so: D = 15^2-4*1*(-34)=361 k = (-15 (+-) sqrt(361))/(1*2) k = (-15 (+-) 19)/2 k = 2 V k = -17 then again it is hard to make a negative garden so 2 most be the answer. (if the premises i made in the start are correct)
thanks that sounds right
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