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Hi, perform the following operation: (x-3)(3x-2y) I just need to add exponent 2 to the first X
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\[(x ^{2}-3)(3x-2y)\]
this is multiplication this explains how to do it http://www.khanacademy.org/math/algebra/polynomials/v/multiplying-polynomials1
= \[4x ^{3}+15x ^{2}y-12x-45y\]
when I multiply it, I get this:
\[3x ^{3}-2x ^{2}y-9x+6y\]
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your last expression looks good.
I know, but the teacher said that the first expression is the answer?
the other expression \[ 4x^3 + 15x^2 y -12 x -45 y = (x^2-3)(4x+15y) \] looks like a case of miscommunication
Yea, maybe she gave the wrong answer. It happens. Thanks.
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