Question

i don't understand the example:

Answer 1

\[\left(\begin{matrix}\frac{ p+1 }{ 2 } \\ \end{matrix}\right)^{2}+(p+1)^{3}\]
= \[\left(\begin{matrix}\frac{ p+1 }{ 2 } \\ \end{matrix}\right)^{2}.1 + \left(\begin{matrix}\frac{ p+1 }{ 2 } \\ \end{matrix}\right)^{2}\frac{ (p+1)^3 }{ \left(\begin{matrix}\frac{ p+1 }{ 2 } \\ \end{matrix}\right)^{2}}\]

Answer 2

@cwrw238 @ganeshie8 @satellite73

Answer 3

@Carl_Pham @experimentX @Sam.

Answer 4

huh ... that's pretty obvious
\[ a + b = a+ {a \times b \over a}\]

Answer 5

let
\[ \left( p+1 \over 2\right)^2 = a \text{ and } (p+1)^3 = b \]

Answer 6

but why are they dividing by a...

Answer 7

wait @experimentX , so they divide by a so that they can have a common denominator?

Answer 8

really i don't know ... probably so that they can take common


well i thought i would easily copy your latex ... but you seem to type complex expression.

Answer 9

\[ \left( p+1 \over 2\right)^2 \left( 1 + {(p+1)^3 \over \left( p+1 \over 2\right)^2}\right)\]

Answer 10

its fine , thank you for the help :)