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at what point is the tangent to f(x) = x^2 + 4x - 1 horizontal? im not sure if it matters with this but i got the derivative 2x + 4
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the tangent is horizontal when the slope is xero
yup horizontal means it is zero
although i do like xero
linkin park
ok but i need a point
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Misread as finding the tangent to that line, sorry.
set the derivative = 0..get x
plug x in...the original eqn..get y
oooohh yes! derp. lol. thank you!
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