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Mathematics 11 Online
OpenStudy (anonymous):

at what point is the tangent to f(x) = x^2 + 4x - 1 horizontal? im not sure if it matters with this but i got the derivative 2x + 4

OpenStudy (anonymous):

the tangent is horizontal when the slope is xero

OpenStudy (anonymous):

yup horizontal means it is zero

OpenStudy (anonymous):

although i do like xero

OpenStudy (anonymous):

linkin park

OpenStudy (anonymous):

ok but i need a point

OpenStudy (cgreenwade2000):

Misread as finding the tangent to that line, sorry.

OpenStudy (anonymous):

set the derivative = 0..get x

OpenStudy (anonymous):

plug x in...the original eqn..get y

OpenStudy (anonymous):

oooohh yes! derp. lol. thank you!

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