Is there a horizontal asymptote in this function? y = (x+2)/((x−1)(x^2+3))
Best way is to draw your function.
I have it graphed
Just because it appears on the graph that there is a horz. asymptote doesn't mean that it exists.
vertical asymptote where the denominator is zero, namely \(x=1\)
right, got that part.. but the graph looks like it might have a horz. asymptote at y=0
horizontal asymptote is \(y=0\) since the degree of the numerator is smaller than the degree of the denominator
is that a general rule?
degree of numerator is 1, degree of denominator is 3 yes
okay, well then. How do i prove it using limits.. if we take the limit as x->1 it approaches infinity from both sides, but what about the horz. asym.?
I've only ever used limits with vertical asymptotes but I don't really know... I would go with what satellite is saying because i have also heard that general rule.
@satellite73, is there a way to prove it using limits?
it is obvious, but yes, you can think of what you would get if you replace \(x\) by \(10^6\)
you would have \(10^6\) in the numerator, but you would have \(10^{18}\) in the denoninator
get a number close to zero
sure do
i see.. alrighty thanks.
yw
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