simplify: (2)log5 (12)-log5 (12)-log5 (8)-(2)log5(3)
the 5... is that log base 5? is that what you are saying?
yes
ok. Because they all have the same base you can do some simplifying through some logarithmic laws. First, if there is a coefficient in front of the log it is the same as...\[2\log_{5} 12\rightarrow \log_{5} 12^{2}\]Do you see how the coefficient can become the power? Do all of these first.
do not do it for the - sign tho. meaning don't say that is the same as -1, even tho it is, you'll see why here in a minute.
if you see a log with all the same bases and they are being subtracted that is the same as...\[\log_{5} x-\log_{5} y-\log_{5}z \rightarrow \log_{5} (x \div y \div x)\]
i got log5(1)
I got something different.
log(144/12/8/9)
log5 (1/6)
Thats what I got
Let me know if I'm wrong, its possible
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