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OpenStudy (anonymous):
the 5... is that log base 5? is that what you are saying?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok. Because they all have the same base you can do some simplifying through some logarithmic laws. First, if there is a coefficient in front of the log it is the same as...\[2\log_{5} 12\rightarrow \log_{5} 12^{2}\]Do you see how the coefficient can become the power? Do all of these first.
OpenStudy (anonymous):
do not do it for the - sign tho. meaning don't say that is the same as -1, even tho it is, you'll see why here in a minute.
OpenStudy (anonymous):
if you see a log with all the same bases and they are being subtracted that is the same as...\[\log_{5} x-\log_{5} y-\log_{5}z \rightarrow \log_{5} (x \div y \div x)\]
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OpenStudy (anonymous):
i got log5(1)
OpenStudy (anonymous):
I got something different.
OpenStudy (anonymous):
log(144/12/8/9)
OpenStudy (anonymous):
log5 (1/6)
OpenStudy (anonymous):
Thats what I got
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