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Mathematics 13 Online
OpenStudy (anonymous):

Dana plans to cover this model of a half moon completely with silver foil. How many square centimeters of silver foil would Dana need to cover the model completely? 402.2 536.2 603.4 150.8

OpenStudy (anonymous):

OpenStudy (anonymous):

Dude, this is a homework help site, do not ask for emails :P

OpenStudy (anonymous):

its not and ur a player

OpenStudy (anonymous):

true @trackzz

OpenStudy (campbell_st):

well the surface area of a hemisphere is \[SA = \frac{1}{2}(4pir^2) + \pi r^2\] and you have a radius of 8 cm just substitute and solve.

OpenStudy (anonymous):

i dont know how to do that

OpenStudy (anonymous):

cause i just see leters

OpenStudy (anonymous):

@campbell_st

OpenStudy (campbell_st):

ok... do you have a calculator ?

OpenStudy (anonymous):

yesss

OpenStudy (campbell_st):

ok you need to type in \[0.5 \times 4 \times \pi \times 8^2 + \pi \times 8^2\] that will give the answer to covering the hemisphere in foil..

OpenStudy (anonymous):

Alrii so basically what campbell has show you is the surface are of a sphere. Any problem in which they ask for something that wraps around a specific shape involves surface are. The surface area of a sphere is: 4 pi r^2 Where r is the radius of the sphere.

OpenStudy (anonymous):

what is p 12.18 or 12.14

OpenStudy (anonymous):

If you're familiar with the button pi, it is the value of 3.14. Now for this particular question, it is a hemisphere. So half the surface are of the sphere. 1/2*(4pi r^2) = SA

OpenStudy (anonymous):

thnks

OpenStudy (anonymous):

@crystal1 what are you talking about>

OpenStudy (anonymous):

you said:" what is p 12.18 or 12.14" what do you mean?

OpenStudy (anonymous):

my bad sorry

OpenStudy (anonymous):

so you got the answer?

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

my answer is 5048.1152

OpenStudy (campbell_st):

nope... thats a long way from being correct

OpenStudy (campbell_st):

did you type in the equation I gave you as its written...?

OpenStudy (anonymous):

Shall we break it down Campbell? I think it's the BEDMAS

OpenStudy (anonymous):

Alright crystal, I want you to do r^2 first. Find the value of the radius squared.

OpenStudy (anonymous):

yes i did @campbell_st

OpenStudy (campbell_st):

and tracks... I think you possible solution is missing the circular base... as the question talks about competely covering... it

OpenStudy (anonymous):

you guys lost me now im confuse

OpenStudy (campbell_st):

ok... lets to it in little bits can you calculate \[0.5 \times 4 \times \pi \times 8^2\]

OpenStudy (anonymous):

Ok my bad, alrii yeah you're right. I'll leave this to Campbell. Dont wanna confuse you,

OpenStudy (campbell_st):

@crystal1 did you get an answer for the new calculation..?

OpenStudy (anonymous):

b

OpenStudy (campbell_st):

what was the number..?

OpenStudy (anonymous):

i dont reaally know im sorry im dumb i dont know how to start this thats why i need help

OpenStudy (anonymous):

You're not dumb. Tell yourself you're smart. You'll get the answer. Crystal, you got this. Wake up, look at what campbell wrote for you.

OpenStudy (anonymous):

the answer is a

OpenStudy (anonymous):

you're not finished yet. Add the pi r^2 to what you got to get the answer

OpenStudy (campbell_st):

nope thats only the 1st part of the problem the curved surface has an area of 402.2 cm^2 now you need to find the area of the circular base... \[\pi \times 8^2\]

OpenStudy (campbell_st):

you need to calculate this number...

OpenStudy (campbell_st):

then the final answer will be \[402.2 + \pi \times 8^2 = \]

OpenStudy (anonymous):

6485.44

OpenStudy (campbell_st):

wow... nope not it lets make it easier what is \[\pi \times 8^2 =\]

OpenStudy (anonymous):

75.36

OpenStudy (campbell_st):

nope still not right... \[\pi \times 8^2 = 201.1\]

OpenStudy (anonymous):

how do you get thaat i tough that 8x2 its = 24

OpenStudy (campbell_st):

do you know how to square a number...

OpenStudy (anonymous):

no

OpenStudy (campbell_st):

ok... then perhaps you need to ask you teacher... how to do the problem is you don't know the basics...

OpenStudy (anonymous):

thnks you @campbell_st

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